**10th Maths Book Back Question and Answers – Chapter 3 Exercise 3.6:**

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**Samacheer Kalvi 10th Maths Book Back Answers – Ex 3.6 Algebra**

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**Chapter 3**

**Exercise 3.6 Algebra**

1. Simplify

**Solution:**

2. Simplify

**Solution:**

3. Subtract 1×2+2 from 2×3+x2+3(x2+2)2

**Solution:**

4. Which rational expression should be subtracted from x2+6x+8×3+8 to get 3×2−2x+4

**Solution:**

5.

6. If A = xx+1, B = 1x+1, prove that

7. Pari needs 4 hours to complete a work. His friend Yuvan needs 6 hours to complete the same work. How long will be take to complete if they work together?

**Answer:**

Let the work done by Pari and Yuvan together be x

Work done by part = 14

Work done by Yuvan = 16

By the given condition

14 + 16 = 1x ⇒ 3+212 = 1x

512 = 1x

5x = 12 ⇒ x = 125

x = 2 25 hours (or) 2 hours 24 minutes

8. Iniya bought 50 kg of fruits consisting of apples and bananas. She paid twice as much per kg for the apple as she did for the banana. If Iniya bought Rs. 1800 worth of apples and Rs. 600 worth of bananas, then how many kgs of each fruit did she buy?

**Answer:**

Let the quantity of apples and bananas purchased be ‘x’ and ‘y’

By the given condition

x + y = 50 ………(1)

Cost of one kg of apple = 1800x

Cost of one kg of banana = 600y

By the given condition

One kg of apple = 2(600)y

Total cost of fruits purchased = 1800 + 600

x × 2 (600)y + y (600)y = 2400

1200xy = 2400 – 600

1200xy = 1800

1200 x = 1800 × y

x = 1800×1200 = 3y2

Substitute the value of x in (1)

3y2 + y = 50

5y2 = 50

5y = 100 ⇒ y = 1005 = 20

x = 3y2 = 3×202

= 30

The number of apples = 30 kg

The number of bananas = 20 kg

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