06 Apr 2022

Samacheer kalvi 10th Maths – Algebra Ex. 3.14

10th Maths Book Back Question and Answers – Chapter 3 Exercise 3.14:

Samacheer Kalvi 10th Standard Maths Book Back Questions with Answers PDF uploaded and the same given below. Class-tenth candidates and those preparing for TNPSC exams can check the Maths Book Back Answers PDF below. Samacheer Kalvi Class 10th Std Maths Book Back Answers Chapter 3 Exercise 3.14 Solutions are available below. Check the complete Samacheer Kalvi 10th Maths – Algebra Ex 3.14 Book Back Answers below:

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For the complete Samacheer Kalvi 10th Maths Book Back Solutions Guide PDF, check the link – Samacheer Kalvi 10th Maths Book Back Answers




Samacheer Kalvi 10th Maths Book Back Answers – Ex 3.14 Algebra

Samacheer Kalvi 10th Maths Book Subject One Mark, Two Mark, Five Mark Guide questions and answers are below. Check Maths Book Back Questions with Answers. Take the printout and use it for exam purposes.

For Samacheer Kalvi 10th Maths Book PDF, check the link – 10th Maths Book PDF

Chapter 3

Exercise 3.14 Algebra

1. Write each of the following expressions in terms of α + β and αβ.
10th maths unit - 3 book back answer

Solution:

10th maths unit - 3 book back answer

2.The roots of the equation 2x2 – 7x + 5 = 0 are α and β. Without solving the root find
10th maths unit - 3 book back answer

Solution:
2x2 – 7x + 5 = x2 – 72x+52 = 0
α + β = 72
αβ = 52

10th maths unit - 3 book back answer

10th maths unit - 3 book back answer

3.The roots of the equation x2 + 6x – 4 = 0 are α, β. Find the quadratic equation whose roots are
(i) α2 and β2
(ii) 2α and 2β
(iii) α2β and β2α
Solution:
If the roots are given, the quadratic equation is x2 – (sum of the roots) x + product the roots = 0.
For the given equation.
x2 + 6x – 4 = 0
α + β = -6
αβ = -4
(i) α2 + β2 = (α + β)2 – 2αβ
= (-6)2 – 2(-4) = 36 + 8 = 44
α2β2 = (αβ)2 = (-4)2 = 16
∴ The required equation is x2 – 44x – 16 = 0.
10th maths unit - 3 book back answer

(iii) α2β + β2α = αβ(α + β)
= -4(-6) = 24
α2β × β2α = α3β3 = (αβ)3 = (-4)3 = -64
∴ The required equation = x2 – 24x – 64 – 0.

4.If α, β are the roots of 7x2 + ax + 2 = 0 and if β – α = −137 Find the values of a.
Solution:

10th maths unit - 3 book back answer

5.If one root of the equation 2y2 – ay + 64 = 0 is twice the other then find the values of a.
Solution:
Let one of the root α = 2β
α + β = 2β + β = 3β
Given
10th maths unit - 3 book back answer

a2 = 576
a = 24, -24

6. If one root of the equation 3x2 + kx + 81 = 0 (having real roots) is the square of the other then find k.
Solution:
3x2 + kx + 81 = 0
Let the roots be α and α2
10th maths unit - 3 book back answer

Other Important Links for 10th Maths Book Back Answers Solutions:

For 10th Maths Chapter 3 book back question and answers, check the link – Samacheer kalvi 10th Maths Chapter 3 Algebra

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